I just checked it out with C# and it shows exactly the same behaviour. I
expected it to do
x = 3;
y = x;
rather than
x = 3;
y = 3;
Very interesting and good to know.
I think that it is pretty consistent and expected behaviour not only in
Vala but in other languages as well (as long as they allow such things). I
would be worried if it would work other way around. Example:
int x, y;
x = 2;
y = x = 3;
I expect that both y and x will have same value, 3. I would not like to get
y=2 and x=3.
I hope that this clears things up but I also wonder in which language it
works differently.
JC
2012/11/1 foracc <for...@d00m.info>
Hello list,
I stumbled on some (for me) unexpected behaviour when setting and getting
a property at the same time, which is not consistend with simple types like
int.
When doing something like
int x = (myclass.myproperty = y);
x will be set to y, and not whatever mycalss.myproperty will be (or what
was mycalss.myproperty set to before). Is this a limitation of Vala?
The code below shows this behaviour and should be pretty self-explanatory.
---------- snip ----------
public class myclass : Object
{
private int _number;
public int number {
set { _number = value * 2; }
get { return _number; }
}
}
public void main(string[] args)
{
myclass m = new myclass();
int i = 2;
m.number = 2;
// prints 4, ok
stdout.printf("number: %d\n", m.number);
// prints 3, not 6 (or at least 4)
stdout.printf("number: %d\n", m.number = 3);
// prints 6, ok
stdout.printf("number: %d\n", m.number);
/ prints 5, ok
stdout.printf("i: %d\n", i = 5);
}
---------- snip ----------
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