If you want to execute code on Object creation using Object.new(), you
should use
construct {
// Your code here
}
When define code at MyObject.new(), you execute the code in this method not
Object.new(), then use the above should help.
2016-02-16 15:58 GMT-06:00 Andy Lees <andrewl...@gmail.com>:
> The problem with Object.new is that it doesn't call the object constructor
> so far as I can tell, just calling g_object_new without any of the Vala
> object construction code.
>
> My Serializable is an interface. I'm trying to make use of the Json
> serialization framework, and for the most part it's working. The problem
> I'm having is with the construction of instances of array types - there
> appears to be no factory framework for object creation in Vala, and so far
> the only workaround I've come up with is very clunky.
>
> Is there an object factory somewhere that someone could point me towards?
>
> On Wed, Feb 17, 2016 at 1:49 AM, Daniel Espinosa <eso...@gmail.com> wrote:
>
>> Try use Object.new(typeof(IntArr))
>>
>> Try to rename type() to any other, to avoid conflics with Object.type()
>>
>> You are trying to implement Gee.ArrayList<>, may you:
>>
>> A) wrap Gee.ArrayList in your class
>>
>> B) Derive directly from Gee.Arraylist then convert your base class
>> Serializable as an interface with all required methods implemented as
>> virtual, then you have two bases.
>>
>> You may want to check at GXml.Serializable interface and its
>> GXml.SerializableArrayList implementation based on Gee.
>> El feb. 16, 2016 7:10 AM, "Andy Lees" <andrewl...@gmail.com> escribió:
>>
>>> I would have expected the generic type to be obtained from the type id
>>> of the derived type (generic instantiation), which is obtained fresh each
>>> execution, but it seems not. Is the generic type a hidden property of the
>>> class derived from the generic class, and if so, what would its name be so
>>> that it can be set in the new call?
>>>
>>> Alternatively, is there a way to call an object constructor given the
>>> type id?
>>>
>>> On Tue, Feb 16, 2016 at 11:16 PM, Daniel Espinosa <eso...@gmail.com>
>>> wrote:
>>>
>>>> Take in account that Type system is dynamically created, then a type
>>>> number will change with each execution.
>>>>
>>>> Use
>>>>
>>>> YourCreatedObject is typeof (Object)
>>>>
>>>> to check if the created object is of type you need, like a derived
>>>> object.
>>>>
>>>> You can use
>>>>
>>>> obj.get_type().is_a(typeof (Object))
>>>>
>>>> And consider that your example is exactly the way to create an object
>>>> of Generic class, because you have set tje object type. Create a generic
>>>> instance with Object.new you should provide the object type.
>>>> El feb. 16, 2016 5:14 AM, "Andy Lees" <andrewl...@gmail.com> escribió:
>>>>
>>>>> Hi,
>>>>>
>>>>> I have a generic array implementation like so:
>>>>>
>>>>> public class GArrSerializable<T> : Serializable, Object {
>>>>> public T[] data;
>>>>> public int length;
>>>>> public GArrSerializable(int size = 0) {
>>>>> data = new T[size];
>>>>> }
>>>>>
>>>>> public Type type () { return typeof (T); }
>>>>>
>>>>> ...etc
>>>>>
>>>>> and a derived type:
>>>>>
>>>>> public class IntArr : GArrSerializable<int> {
>>>>>
>>>>> public IntArr(int size = 0) {
>>>>> base (size);
>>>>> }
>>>>> }
>>>>>
>>>>> If I create an instance of the type, then instance.type () returns 24
>>>>> as
>>>>> expected.
>>>>> If I create an instance like so:
>>>>> var ia = Object.@new (type) as IntArr;
>>>>> var t = ia.type ();
>>>>>
>>>>> Then t is 4 rather than 24. As it is in the instance when it tries to
>>>>> deserialize.
>>>>>
>>>>> Can you tell me why this is so, and how I can programmatically create
>>>>> objects derived from a parameterised type?
>>>>>
>>>>> Thanks
>>>>>
>>>>> Andrew Lees
>>>>> _______________________________________________
>>>>> vala-list mailing list
>>>>> vala-list@gnome.org
>>>>> https://mail.gnome.org/mailman/listinfo/vala-list
>>>>>
>>>>
>>>
>
--
Trabajar, la mejor arma para tu superación
"de grano en grano, se hace la arena" (R) (en trámite, pero para los
cuates: LIBRE)
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