On 08/31/17 05:46, Nor Jaidi Tuah wrote:
>
>> int c1 = f_add(a)(b);
>> int c2 = f_add2(a, b); //Problem here
>>
>
> try f_add2(a,b)()
>
>
> Nice day
> Nor Jaidi Tuah
Hi Nor/Al/others,
Thanks for responding to my query.
I could make my code work by calling it with f_add2()(a, b). This leads
me to think generally as under.
If a declare a delegate like this :
delegate return_type _DG_xyz(argset_1);
and then define a function which will return using above lambda
_DG_xyz fx(argset_2)
{
//lambda-expression
}
Then argset_1 and argset_2 are independent of each other. argset_1
corresponds to the arguments for the lambda-expression, not for the
client function fx. fx can use any argument list of its own and do
anything as long as it returns [a function pointer to] a lambda that
uses argset_1
Am I right about my conclusion ?
Manish Jain
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