Have you tried with --fair-sched=yes, as suggested in an earlier mail ?
What were/are the results ?

Philippe

On Wed, 2018-02-07 at 07:52 +0000, Wuweijia wrote:
> Hi:
>       There are some news about this question. The new code as below,  I 
> change from  __sync_fetch_and_add to  pthread_mutex_xxx
>       
>         pthread_mutex_lock(&g_mutex);
>         int curr = m_nCurrent;
>         m_nCurrent += m_nStep;
>         pthread_mutex_unlock(&g_mutex);
>       
>       Now there is no testcases with valgrind running too long, and failed.
>                 
>       But pthread_mutex_lock is not efficient as __sync_fetch_and_add,   so 
> the pthread_mutex_lock is just for now, for testing.
> 
>       And I think there is something related to schedule module of valgrind . 
> why it last too long?
> 
> BR
> Owen
> 
> 
> -----邮件原件-----
> 发件人: John Reiser [mailto:jrei...@bitwagon.com] 
> 发送时间: 2018年1月26日 12:44
> 收件人: valgrind-users@lists.sourceforge.net
> 主题: Re: [Valgrind-users] 答复: 答复: 答复: [Help] Valgrind sometime run the program 
> very slowly sometimes , it last at least one hour. can you show me why or 
> some way to analyze it?
> 
> On 01/25/2018 15:37 UTC, Wuweijia wrote:
> 
> >     Function1:
> > bool CDynamicScheduling::GetProcLoop(
> >          int& nBegin,
> >          int& nEndPlusOne)
> > {
> >          int curr = __sync_fetch_and_add(&m_nCurrent, m_nStep);
> 
> How large is 'm_nStep'?  [Are you sure?] The overhead expense of switching 
> threads in valgrind would be reduced by making m_nStep as large as possible.  
> It looks like the code in Function2 would produce the same values regardless.
> 
> 
> >          if (curr > m_nEnd)
> >          {
> >                  return false;
> >          }
> > 
> >          nBegin = curr;
> >          int limit = m_nEnd + 1;
> 
> Local variable 'limit' is unused.  By itself this is unimportant, but it 
> might be a clue to something that is not shown here.
> 
> >          nEndPlusOne = curr + m_nStep;
> >          return true;
> > }
> >     
> >     
> >     Function2:
> >     ....
> >     int beginY, endY;
> >    while (pDS->GetProcLoop(beginY, endY)){
> >      for (y = beginY; y < endY; y++){
> >        for(x = 0; x < dstWDiv2-7; x+=8){
> >          vtmp0 = vld2q_u16(&pSrc[(y<<1)*srcStride+(x<<1)]);
> >          vtmp1 = vld2q_u16(&pSrc[((y<<1)+1)*srcStride+(x<<1)]);
> 
> I hope the actual source contains a comment such as:
>      Compute pDst[] as the rounded average of non-overlapping 2x2 blocks of 
> pixels in pSrc[].
> 
> >          vst1q_u16(&pDst[y*dstStride+x], (vtmp0.val[0] + vtmp0.val[1] + 
> > vtmp1.val[0] + vtmp1.val[1] + vdupq_n_u16(2)) >> vdupq_n_u16(2));
> >        }
> >        for(; x < dstWDiv2; x++){
> >          pDst[y*dstStride+x] = (pSrc[(y<<1)*srcStride+(x<<1)] + 
> > pSrc[(y<<1)*srcStride+(x<<1)+1] + pSrc[((y<<1)+1)*srcStride+(x<<1)] + 
> > pSrc[((y<<1)+1)*srcStride+((x<<1)+1)] + 2) >> 2;
> >        }
> >      }
> >    }
> > 
> >    return;
> > }   
> 
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