Hi, On Mon, Nov 17, 2014 at 4:43 PM, T. Pascal <[email protected]> wrote:
> I'll have to assign the contents of the replacement group to a variable > and then lower that variable and then substitute it back in? > > That's three or four vcl lines to accomplish something that seems like a > workaround to a bug. :) > \1 won't work (how you expect) in string context, only in a regular expression. Perl won't let you do this with \1 either. However, in Perl you have $1 which I think will do what you want to. So I can understand the confusion. Per. -- *Per Buer* CTO | Varnish Software AS Cell: +47 95839117 We Make Websites Fly! www.varnish-software.com [image: Register now] <http://info.varnish-software.com/varnish-summits-autumn-2014-registration>
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