Hello all,
I have a question about debuging VirtualBox in Linux environment.
It seems the breakpoint doesn't got been hit.
First I compile a debug version of VirtualBox.
1. start a vm: sudo gdb --args ./VirtualBox --comment ubuntu --startvm
a3af2e12-957b-48a8-8b0c-1afe93fe2d2c --no-startvm-errormsgbox
2. set break point. For example:
b vpciIOPortOut
3. in the guest, we trigger an IO access.
outw(1,0xd020+0xe)
4. In my mind, I think this will break at vpciIOPortOut function. But it
doesn't, the vm just run without break.
5. But as I change the outw to outl/outb.(This will make the 'cb' to be 1 or 4.
The VM will crash.
This crash is caused by following Assert in vpciIOPortOut function.
case VPCI_QUEUE_SEL:
Assert(cb == 2);
u32 &= 0xFFFF;
if (u32 < pState->nQueues)
pState->uQueueSelector = u32;
else
Log3(("%s vpciIOPortOut: Invalid queue selector %08x\n",
INSTANCE(pState), u32));
break;
So here I think outb/w/l in guest does TRIGGER the call of vpciIOPortOut
function. But why does the vm not pause and goto gdb? Is there something I
missed?
Thanks.
--
Li Qiang /the Gear Team, Qihoo 360 Inc_______________________________________________
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