> > if runtime.id == 1: > > a = runtime.broadcast(1, "foo") > > b = runtime.broadcast(2) > > if runtime.id == 2: > > a = runtime.broadcast(1) > > b = runtime.broadcast(2, "bar") > > if runtime.id == 3: > > a = runtime.broadcast(1) > > b = runtime.broadcast(2) > > > > This does not match the shamir_share method, which allows you to write > > > > a, b = runtime.shamir_share([1, 2], input) > > > > where input is different for each of the two inputters. > > That code is actually wrong, the correct code would be: > > if runtime.id == 1 or runtime.id == 2: > a, b = runtime.shamir_share([1, 2], input) > else: > a, b = runtime.shamir_share([1, 2]) This code assumes that the input is already determined above based on whether we have id 1 or 2. So there is somehow the same branch as in the broadcast case, only hidden here.
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