I'm having a mental block, how can I wrap a string via substitute() ?
I've been trying something like:
let str = "123456789012345678901234567890"
let str = substitute(str, '\n\([[:print:]]\{-10,}\)', '\n\1\n', '')
echo str
to produce:
1234567890
1234567890
1234567890
The following seems to do the trick for me:
echo substitute(str, '[[:print:]]\{,10}', '&\n', 'g')
which should also gracefully handle
"123456789012345678901234567890123"
(with the extra trailing 123 at the end, making it a non-even
multiple of 10)
-tim
