In this example I think it´s easy:
[from line],[to line]s/ //
and applicated twice. It only deletes every time the
first space.
Dada
--- Dudley Fox <[EMAIL PROTECTED]> schrieb:
> Hello Vim List,
> I have used vim for a while, and though no expert I
> am fairly
> comfortable with the common commands. Recently I ran
> into a situation
> where I just couldn't find a way to do a search and
> replace. I was
> hoping some of you experts could help me out.
>
> Starting text:
> nameTable[pattern with spaces0] = ("pattern with
> spaces0", 12345)
> nameTable[pattern with spaces1] = ("pattern with
> spaces1", 67890)
> nameTable[pattern with spaces2] = ("pattern with
> spaces2", 243)
> nameTable[pattern with spaces3] = ("pattern with
> spaces3", 421)
> nameTable[pattern with spaces4] = ("pattern with
> spaces4", 3455)
> nameTable[pattern with spaces5] = ("pattern with
> spaces5", 2222)
>
> Desired Text:
> nameTable[patternwithspaces0] = ("pattern with
> spaces0", 12345)
> nameTable[patternwithspaces1] = ("pattern with
> spaces1", 67890)
> nameTable[patternwithspaces2] = ("pattern with
> spaces2", 243)
> nameTable[patternwithspaces3] = ("pattern with
> spaces3", 421)
> nameTable[patternwithspaces4] = ("pattern with
> spaces4", 3455)
> nameTable[patternwithspaces5] = ("pattern with
> spaces5", 2222)
>
>
> Notice that the only difference is that the spaces
> are removed from
> the pattern in between the square brackets. I think
> I want to use \zs
> and \ze, but I couldn't wrap my head around the
> syntax. Any help would
> be appreciated.
>
> Sincerely,
> Dudley
>
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