Nikolaos A. Patsopoulos wrote:
Hi,

I have a text that has many occurrences of a pattern . I want to delete every consecutive occurrence, e.g.

Pattern Pattern other text Pattern Pattern Pattern Pattern other text Pattern Pattern Pattern
should look like this:
Pattern other text Pattern other text Pattern

I've used:

:%s/\(Pattern\s\+\)\(Pattern\)/\1/g

but have to run this more than once with: %&g to result the wanted text.

Can I do this with one command only? If not can I write a while function?:

while patternDoNotMatch
   %s/\(Pattern\)\(Pattern\)/\1/g
endwhile

Thanks in advance,

Nikos


Assuming it's the _word_ Pattern, not any text that verifies a certain _regular expression_ you can use (untested):

        :%s/\(Pattern\_s*\)*/Pattern /g



Best regards,
Tony.
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Five is a sufficiently close approximation to infinity.
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