Hi,
I have been playing with shellescape() lately and I think I have found
at least one bug with how shellescape() works and have one suggestion
for :h shellescape() to make thinks clear.
Basically I wanted to execute printf "10,02d\n". So here is the script:
let a='printf "10,%02d\n" 1'
:exe '$r!'.shellescape(a,1)
I expected it to return 10,01. But it didn't. It returned this error:
bash: printf "10,%02d\n" 1: command not found
I believe it does this, because bash is trying to execute the command
'printf "10,%02d\n"', which obviously does not exist. So apparently you
have to shellescape each argument to the command separately, before
executing the whole command, right?
Something like this, should work?
let a='find /tmp/files -type f -name "*" -print -exec chmod 764 {} ;'
exe ":!".join(map(split(a), 'shellescape(v:val,1)'), ' ')
If this is true, I think the documentation :h shellescape() should be
updated, like this, to make that clear:
--- /home/chrisbra/local/share/vim/vim72/doc/eval.txt.old 2009-10-15
21:15:03.000000000 +0200
+++ /home/chrisbra/local/share/vim/vim72/doc/eval.txt 2009-10-15
22:19:45.000000000 +0200
@@ -5003,7 +5003,9 @@
will enclose {string} in double quotes and double all double
quotes within {string}.
For other systems, it will enclose {string} in single quotes
- and replace all "'" with "'\''".
+ and replace all "'" with "'\''". If you need to escape a
+ commandline consisting of several arguments, you have to
+ escape each argument separately.
When the {special} argument is present and it's a non-zero
Number or a non-empty String (|non-zero-arg|), then special
items such as "!", "%", "#" and "<cword>" will be preceded by
And while we are at shellescape(), I think there is also this bug:
:exe ':r! printf '.shellescape("10%%")
which returns surprisingly:
,----
| 10/tmp/mutt-256bit-1004-14268-177/tmp/mutt-256bit-1004-14268-177
`----
instead of 10%.
Mit freundlichen Grüßen
Christian
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