On 17:42 Sat 17 Nov , rail shafigulin wrote:
> On Sat, Nov 17, 2012 at 4:16 PM, Christian Brabandt <cbli...@256bit.org>wrote:
>
> > Hi rail!
> > (please don't top poste)
> >
> > On Sa, 17 Nov 2012, rail shafigulin wrote:
> >
> > > I'm still no quite clear. So when I set shiftround it moves the code by
> > the
> > > length of shiftwidth-1 when I use the >> or << ?
> >
> > No, if it is set, it moves it to the next multiple value of shiftwidth,
> > while when it is not set, it simply moves by shiftwidth chars.
> >
> > Here is an example:
> > If your shiftwidth value is 4 and your input starts at cell 3 indenting
> > using >> would move the text to cell 5 if shiftround is set, while it
> > moves your text to cell 7 when shiftround is not set.
> >
> > regards,
> > Christian
> > --
> > Den (inländischen) Ruhm großer Minister, Feldherrn, Fürsten stürzt
> > eine einzige Staatsumwälzung oder Eroberung.
> > -- Jean Paul
> >
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> >
>
> The "next multiple value of shiftwidth" confuses me. So if shiftwidth is 8,
> will the next multiple be 2, 4 or 8? How about shiftwidth of 7, will the
> next multiple be 7 ?
>
> Any help is appreciated.
>
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Indeed, if you set shift width to 7 and the first non blank character
is at column 9 then '>>' will move it to the column 14 when 'shiftround'
is set and to column 9+7=16 when it is not set. The operator << will
move it to the column 7 when 'shiftround' is set and 9-7=2 when it is
not set.
Best,
Marcin
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