Hello Sherman, > Virtuoso 37000 Error SP030: SPARQL compiler, line 3: syntax error at 'SPARQL' > before 'INSERT' > > SPARQL query: > > #output-format:text/html > define sql:signal-void-variables 1 SPARQL INSERT IN GRAPH > <http://BookStore.com> > { <http://www.dajobe.org/foaf.rdf#i> <http://purl.org/dc/elements/1.1/date> > <1999-04-01T00:00:00> . > <http://www.w3.org/People/Berners-Lee/card#i> > <http://purl.org/dc/elements/1.1/date> <1998-05-03T00:00:00> . > <http://www.w3.org/People/Connolly/#me> > <http://purl.org/dc/elements/1.1/date> <2001-02-08T00:00:00> };
When used in stored procedure or called via ISQL, it should be SPARQL define sql:signal-void-variables 1 INSERT IN GRAPH ... When called via SPARQL web service endpoint, the SPARQL keyword is not needed at all. "SPARQL" is a Virtuoso SQL keyword that indicates where SPARQL-to-SQL front-end should start to read the text (and to replace the source SPARQL text with compiled SQL fragment). So it should be placed before DEFINE. Web service endpoint does not need this keyword because it does not expect anything other than SPARQL and it don't have to distinguish between SPARQL and surrounding SQL. Best Regards, Ivan Mikhailov OpenLink Software http://virtuoso.openlinksw.com
