Alexandre Bertails wrote:
"If there is no |FROM| clause, but there is one or more |FROM
NAMED| clauses, then the dataset includes an empty graph for
the default graph."
Is this the expected (not "excepted", sorry) behaviour ?
In a nutshell, yes :-)
FROM NAMED does not implicitly negate the existence of a default
graph. This is why GRAPH ?g or GRAPH <http://test1> is required to
set scope of your patterns to Named Graphs explicitly.
Ok I understand what Virtuoso does and I am able to obtain the good quads
But I still don't understand the meaning of "the dataset includes an
empty graph for the default graph".
What does that mean for you ?
Alexandre.
Alexandre,
We've had a chat about this internally and there is a little bug here.
You shouldn't have "anything" where you currently have "everything" :-)
This is a subtle SPARQL spec oversight on our part.
Kingsley
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Regards,
Kingsley Idehen Weblog: http://www.openlinksw.com/blog/~kidehen
President & CEO
OpenLink Software Web: http://www.openlinksw.com
