Hi Sergio,
I would expect "DISTINCT" to work as I used it quite often in SPARQL
queries against Virtuoso.
Can you provide a test case for us to see this problem first hand,
either a server instance we can access online or a dataset we can
load locally to recreate.
The Virtuoso explain function [1] can be used to obtain the query
execution plan for the query and can be run from isql or the
conductor isql interface as follows:
explain('SPARQL SELECT DISTINCT(?name) ?person ?mail WHERE { ?person
rdf:type foaf:Person . ?person foaf:name ?name . ?person
foaf:mbox_sha1sum ?mail}')
If you can provide this output it would be useful for analysis if we
cannot access the server ourselves.
What is the version of the Virtuoso Server you are using ?
[1] http://docs.openlinksw.com/virtuoso/fn_explain.html#(NULL)
Best Regards
Hugh Williams
Professional Services
OpenLink Software
Web: http://www.openlinksw.com
Support: http://support.openlinksw.com
Forums: http://boards.openlinksw.com/support
On 21 Oct 2008, at 08:20, Sergio Fernández wrote:
Hi,
in a experiment I've a dataset with many people (some of then
duplicated). I want just to list it, I'm doing something like:
SELECT DISTINCT(?name) ?person ?mail
WHERE {
?person rdf:type foaf:Person .
?person foaf:name ?name .
?person foaf:mbox_sha1sum ?mail
}
But DISTINCT doesn't work as I expected: if there are duplicated
names,
it returns all. I know that DISTINCT() is not an standard syntax
according to [1]; I've read some example that use it over Virtuoso,
but
I'm not sure about its behaviour.
Thank you in advance.
[1] http://www.w3.org/TR/rdf-sparql-query/#modDistinct
--
Sergio Fernández - sergio.fernan...@fundacionctic.org
R&D Deparment
CTIC Foundation - www.fundacionctic.org
Phone: +34 984 29 12 12
Fax: +34 984 39 06 12
Edificio Centros Tecnológicos
Parque Científico Tecnológico
33203 Cabueñes - Gijón - Asturias - Spain
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