Hello,
While requesting Virtuoso with SPARQL via odbc (with a PHP script), we
have some problems with the received format of the resultset.
Without defining a result-format and with the use of the procedure
DB.DBA.SPARQL_EVAL we get a odbc_resultset, which isn't really usable
for us. We can fetch it into a list of objects for instance, but
literals are received without language or datatype definitions. (With
defining the result-format as RDF/XML, these definitions are included,
but this received data structure must be parsed and wrapped in an other
adequate data structure).
Is there another possibility to get a complex object like an RDF-Box, a
table (with included datatype or language definitions) or something else?
All the Best
Michael Martin
