Hi,
I think I found a bug with the datatype SPARQL function. This query as zero
results :
select distinct count(?birth) count(?death)
where {
?entity <http://dbpedia.org/ontology/birthDate> ?birth .
filter(datatype(?birth) = xsd:date).
OPTIONAL {?entity <http://dbpedia.org/ontology/deathDate> ?death .
filter(datatype(?death) = xsd:date).
}
}
And this query return the good results :
select distinct count(?birth) count(?death)
where {
?entity <http://dbpedia.org/ontology/birthDate> ?birth .
filter(datatype(?birth) =
"http://www.w3.org/2001/XMLSchema#date<http://www.w3.org/2001/XMLSchema#string>
").
OPTIONAL {?entity <http://dbpedia.org/ontology/deathDate> ?death .
filter(datatype(?death) =
"http://www.w3.org/2001/XMLSchema#date<http://www.w3.org/2001/XMLSchema#string>
").
}
}
Have-I missed something or is-it really a bug from Virtuoso 7 ?
Thanks in advance.
Julien.
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