At 8:46 PM 11/28/4, Edmund Storms wrote: >Nice idea, Horace, but you fail to consider one important aspect of using Mg as >the anode. Oxygen that forms at the anode will react to form MgO, which is an >insulator and is insoluble. As a result, cell resistance will increase to >unacceptable values. This same kind of reaction occurs when Zr or Ti are used >as the anode as well. A very low applied current would be the only condition >permitting use of Mg. The current would have to be small enough so that the >formation rate of MgO would have to be less than its rate of dissolution from >the surface.
Yes. I also failed to consider the fact that any (net) current provided through the cell is provided y the only path to the cell, namely through the anode and cathode. This current is provided at the bias potential, so there is no free biasing (power), which was the initial objective. Regards, Horace Heffner
