In reply to  Jones Beene's message of Fri, 04 Mar 2005 07:58:54
-0800:
Hi,
[snip]
>----- Original Message ----- 
>From: "Mark S Bilk"
>
>> Would this reaction  p + 11B -> 3 alphas + 8.7 Mev
>> be a candidate for hydrino fusion (resulting in fission),
>in an
>> electrolytic or plasma-electrolytic cell?  80% of boron
>atoms
>> are 11B, the rest are 10B.  Boric acid (H3BO3) and borax
>(Na2B4O7)
>> are highly soluble in hot water.
>
>Of course it would be the ideal candidate, if boron is a
>catalyst for hydrinos, or if hydrinos generated elsewhere
>can use solid boron as a target.

...or if hydrinos in a "cool" plasma react with B.
Note that the plasma is only for creating hydrinos, and has
nothing to do with the fusion per se.
However having the fusion reaction occur in the plasma itself has
advantages for hydrino production.
[snip]
>> Is the required proton energy for hot fusion of p+11B
>higher
>> than for d+t or d+d?

AFAIK the ideal temperature for D-T is about 110 keV for p-B11
it's somewhere between 800keV and 1.2 MeV.
[snip]
>> If so, does that mean that the proton
>> has to get closer to the B nucleus to fuse, thus requiring
>> an even tinier hydrino than for deuterino+deuterino
>fusion?

Yes. This could be a problem, depending on whether the radius of
the hydrino goes as n or n^2. For the former, it's definitely a
problem, not for the latter.
Note BTW that tunneling of a proton (especially over larger
distances) is much preferred to tunneling of a deuteron, because
it's lighter. Therefore, the easiest reaction for hydrinos to
achieve might actually be p + D -> He3 (light weight particle
tunneling against low Coulomb barrier). Has as disadvantage that
it may need to decay via gamma decay, unless the hydrino's
electron can carry away the energy of the fusion reaction.
[snip]
>Only if the "water" was heavy water, and then the
>cross-section is very low. However the CANDU reactor has
>demonstrated that heavy water under irradiation produces
>"extra" neutrons which are not accounted for in normal
>physics. 

Since reactors produce plenty of fast neutrons, and the binding
energy of D is only 2.2 MeV, might one not expect a few reactions
such as:

n (fast) + D -> H + 2 n (slower)?


>Thus the surprising efficiency of the CANDU, many
>of which have operated at well over 100% for tens of years
>at a stretch.
[snip]

Regards,


Robin van Spaandonk

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