Not a practical idea, just a forced solution, guys. What thermal efrfect could have the lithium from 100 mgr LiAlH4? and Al2O3 is a very stable compound, lithium corrosion is impossible. It is a Li Al lloy there when hyydrogen is out. Waste of time. Peter
On Wed, Feb 11, 2015 at 4:25 PM, Arnaud Kodeck <arnaud.kod...@lakoco.be> wrote: > Alain, > > > > The excess heat generated by Parkhomov’s experiment (if real) is far above > any chemical reaction. 3 Li + 2 Al2O3 -> 3 LiO2 + 4 Al doesn’t produce much > energy. The Li inside the reactor is very small 100 mg? > > > > But Li could corrode the wall of AL203 making it less strong to resist to > the high pressure inside the reactor. > > > > It could be an explanation of the BANG of MFMP. It can’t rule out excess > heat. > > > > Arnaud > ------------------------------ > > *From:* alain.coetm...@gmail.com [mailto:alain.coetm...@gmail.com] *On > Behalf Of *Alain Sepeda > *Sent:* mercredi 11 février 2015 14:48 > *To:* Vortex List > *Subject:* [Vo]:Yevgen Barsukov propose Parkhomov/MFMP reaction is > chemistry > > > > Hi, > > about recent Ni+LiAlH4 experiments done by Parkhomov and MFMP > > on facebook group, Yevgen Barsukov propose that it is a chemical reaction: > > > > > https://www.facebook.com/MartinFleischmannMemorialProject/posts/920127711351262 > > > > "After decomposition of LiAlH4, pure lithium is left. Lithium is reacting > with the walls of the tube made of Al2O3, being a stronger metal than > aluminium it takes away its oxygen with release of heat." > > > > is it an interesting hypothesis to check ? > > > > I think we should also integrate in the reasoning the phase of LiAlH4 > decomposition which is probably endothermic... > > > > What is the total sum ? maybe this mean the reactor swallow heat at the > beginning, and restore more , or less, later... > > > > what is the quantity of heat expected compared to the one AG Parkhomov > measured? > -- Dr. Peter Gluck Cluj, Romania http://egooutpeters.blogspot.com
