The core is producing the electric power and is acting as the negative cathode and the alumina the anode. Perhaps with a grid between for flow control. A grid between might control the electric vs, heat output.
On Thu, Dec 31, 2015 at 3:57 PM, Jones Beene <jone...@pacbell.net> wrote: > *From:* Axil Axil > > Ø Alumina pulls in electrons rather than pushing them out, Is that > correct? > > Technically alumina is a good electrical insulator, as seen in the white > ceramic part of a spark plug. Beta-alumina however is different, and can > be produced in such a way as to conduct only positive ions. As such those > ions would “pull in” electrons after the ions moved through the alumina. > This, in fact, is the way that some sodium batteries operate, using > beta-alumina as a solid electrolyte (oversimplified). I do not think > Rossi is doing this. > > The simplest way to get direct current, if one had a glow tube reactor, > operating inside a larger metal vacuum tube, which functions as an anode, > as you suggest – is to wind the tube with heater wire which also is a good > thermionic emitter like tungsten, then that heater coil itself could also > function as a cathode with a small change in the circuitry. In this case, > it would be wise to use thoriated tungsten as the heater wire, which is > known as a good emitter but needs to be in a vacuum as it is easily > oxidized in air. > > In operation, electrons emitted from the heater coil would decrease the > heat given to the fuel (the Edison effect is a cooling effect). Also, they > would require emf to overcome the space charge inside the gap (like any > vacuum tube). However, if the LENR fuel (by this time) has reached strong > self-sustain mode, with its own ability to produce heat without electrical > input, then this device could be made to function almost like a > self-powered amplifier tube of old. It could possibly function without a > grid accelerator, if enough light was being produced inside the glow tube > (to provide emf and overcome space charge). > > This essentially means that a glow tube which has gone into self-powered > mode (infinite OU) could indeed be arranged to produce electrical current > flow as a side effect, when properly designed inside a vacuum, if the > incandescent photons provide the emf. This is more likely what Rossi is > doing. > > In fact, when net electrical current is being produced, that would be a > STRONG indication that the tube has gone into self-powered mode. As such, > this might even be a better approach then the Parkhomov type of > replication if one has a good vacuum system and a proper Dewar. > > The $64 question is can he provide electrical output with no input for > longer than a few minutes. The thermal inertia of a very hot system could > allow tens of seconds, but not minutes. > > Jones >
