In reply to Jones Beene's message of Thu, 28 Dec 2006 08:20:16 -0800 (PST): Hi Jones, [snip] >--- Robin >Well the "upside-down" part is appropriate...<g> > > >> Furthermore, when it reaches the end of the line, >and is only doing a single orbit for H[n=1/alpha], the >group velocity of the electron is traveling at the >speed of light, which is exactly what Mills predicts >... > >Well, there's the rub. At least according to the >skeptics, and from day-one. Anything approaching this >situation - (which can be restated as repeated >doubling and redoubling of the group velocity of the >electron)- would end up being endothermic, not >exothermic. > >Therefore this cannot be correct, can it? ... since >the electron has substantial mass; not only is pushing >that much mass to lightspeed, or even close ... >totally out of the question, since the electron would >then have more mass-energy equivalent then the nucleus >itself - but where would the energy required to do >this - be coming from?
>From the rest mass lost by proton and electron during shrinkage. Since the electron is continually losing rest mass, while it gains kinetic energy, there comes a point where the next level is unattainable. According to the first graph on my web page (http://users.bigpond.net.au/rvanspaa/New-hydrogen.html) this occurs about q=124 (p=124 to use Mills quantum numbers). However the exact level is irrelevant, for "home grown" Hydrinos, because fusion would occur long before then. The exception being Solar Hydrinos, because fusion on the Sun is paradoxically, much more difficult than here on Earth. That due to the scarcity of target nuclei. Poor Solar Hydrinos, all they ever have as neighbors is other protons. Regards, "Desperately seeking neutron" ;)
