A formula found on a web site says that, for a uniform flywheel, the energy stored is given by:
E = mr^2w^2 / 4 So, for a mass of 1 kg with a radius of 0.25 m and a rotational rate of 120 RPM (4 pi rad/s) the energy stored is 2.47 J. Does this sound right? Does anyone know how to calculate the effect of the 1 kg mass on a vertically loaded tapered thrust bearing? How much load it adds? Terry
