Better: area OK, but power still wrong. Michel
----- Original Message ----- From: "Harry Veeder" <[EMAIL PROTECTED]> To: <vortex-l@eskimo.com> Sent: Monday, February 26, 2007 11:07 AM Subject: Re: [Vo]: New multiwire-plane lifter design guide (was Re: lifter in a accelerating frame) > Michel Jullian wrote: > >> >> Harry wrote: >> >>>> 100 kg thrust, 1 m gap, 0.9 kV/mm >> ... >>> Is this correct? >>> >>> power consumption 9 kW >>> area 3.1 m^2 >>> wire spacing 1.3m >> >> Only the wire spacing is correct, check your power and area calculations. > > > power consumption 90 kW > area 310 m^2 > > Harry > >>> Suggestions: >>> Rephrase the scaling rules to read: >>> >>> "The W per g are proportional to the kV/mm, whereas the m^2 per g are >>> proportional to the inverse square of the kV/mm." >>> >>> I would also explicitly show the mass in the calculation >>> of the area in the example section. >> >> Thanks for the improvements, revised version: >> ********************************************* >> MULTIWIRE-PLANE LIFTER/IONOCRAFT DESIGN GUIDE: >> -------- >> Reference design: At 1 kV/mm (the max we can do without arcing) the power >> consumption is 2 W per "gram" of thrust, and the required area is 0.0025 m^2 >> per g. >> >> Scaling rules: The W per g are proportional to the kV/mm, whereas the m^2 per >> g are proportional to the inverse square of the kV/mm. >> >> Wire: as thin as possible (0.1mm OK in most cases), wire-wire spacing = 1.3 >> times the gap length d (optimum value) >> >> EXAMPLE: >> --------------- >> We want to lift 50 g, and we choose a v/d of half the max value i.e. 0.5 >> kV/mm, namely v=25kV for a d=50mm gap, to save on power consumption (our >> color >> monitor is only 75W) >> >> 1/ Required power per g: 2 W * 0.5 = 1 W -> Power consumption for 50 g = 50 >> W >> 2/ Required area per g: 0.0025 m^2 / 0.5^2 = 0.01 m^2 -> Area for 50 g = 0.50 >> m^2 >> 3/ Wire-wire spacing: 1.3*50 mm = 65mm >> >> ********************************************* >> -- >> Michel >> >> >> >> >
