HF AC
            V1 o--- ---o V2
                  | |
                  OOO
                =======  T1
                OOOOOOO
                |  |  |
      i-->      |  |  |      <--i
   -----M1-------  |  -------M2-----
   |               |               |
   o----C1---------o---------C2----o
   |               |               |
   F1              F2              F3
   |               |               |
   o---(+)DC1(-)---o---(-)DC2(+)---o


  Fig. 1 - Method of superimposing AC signal
           on DC electrolysis current

A frequent objective of electrolysis cell designs is to overcome the DC bias required to push current through the interface layer between the electrolyte and the electrodes while driving the principle electrolysis current from an AC source. Figure 1 shows a method of adding an alternating electrolysis driving current on top of a DC bias in such a way the principle electrolysis current is driven by the AC source.

The electrolytic cells in Figure 1 are designated M1 and M2. These cells can be implemented as series multi-plate cells, so that large voltages can be applied. DC power supplies DC1 and DC2 provide DC potential right at the critical voltage level, where cells M1 or M2 just begin to conduct current and thus perform electrolysis. DC1 and DC2 can contain protection diodes that prevent back current through them. Filters F1, F2 and F3 isolate the DC power supplies from the AC while allowing DC to pass These can simply be large inductors. The center tapped transformer T1 provides current through M1 on one half phase, and M2 on the other half phase. The core of T1 is not biased on average by any DC current because any DC currents through the two secondary windings cancel magnetically. Capacitors C1 and C2 are provided to complete the AC circuit through the cells.

If M1 is exchanged with C1, and M2 exchanged with C2, in Figure 1, then it is easy to see that M1 and M2 can be implemented as a single series multi-plate electrolysis cell with the center plate attached to the center tap of T1, thus avoiding multiple electrolysis cell containers, gas feeds, etc.

Note that the voltage applied in the secondaries of T1 are *incremental* to the voltage supplied by the DC power supplies. Note also that, except for electrolysis cell internal resistance, the active AC elements of the circuit are inductances or capacitances, providing as large a phase angle as possible.

The HF AC power supply is driven at the LC resonance frequency for the AC portion of the circuit. A tuning capacitor or inductor in either the M1 or M2 half of the circuit may be useful to match resonant frequencies for both sides of the circuit.

Figure 2 shows a half circuit version of Figure 1, which lacks the balance of the circuit in Figure 1, but which may be useful if the HF AC power supply can handle the current imbalance and an air core transformer is used for T1, or a transformer not operating near saturation and thus not adversely affected by DC current through the secondary.


                          HF AC
                     V1 o--- ---o V2
                           | |
                           OOO
                          OOOO  T1
                          |  |
                i-->      |  |
             -----M1-------  |
             |               |
             o----C1---------o
             |               |
             F1              F2
             |               |
             o---(+)DC1(-)---o


  Fig. 2 - Method of superimposing AC signal
           on DC electrolysis current - half circuit

Figure 3 shows the AC portion of the half circuit.



                          OOOO  L1
                          |  |
                          |  |
             -----M1-------  |
             |               |
             o----C1---------o

  Fig. 3 - AC portion of electrolysis circuit



Part of the electrolysis efficiency provided by using superimposed AC is provided by the fact the electrolytic cell conducts by two parallel means: (1) ion current conduction and (2) AC capacitive conduction. DC can not use the capacitive conduction path through the cell. By using a superimposed AC current, the current to and through the electrolyte-electrode interface layer is increased for a given cell configuration by activating a second conduction pathway through the electrolyte. The reactance X of a capacitor, the equivalence to DC resistance, for capacitance C and frequency f is:

   X = 1/(2 Pi f C)

When f is in Hz and C in farads then X is in ohms. Therefore, the higher the frequency and the greater the capacitance the more the AC current through the capacitive portion of the electrolyte at a given voltage.

It is notable that all AC current is not Faradaic, i.e. resulting in electrolysis. Though it passes through the electrolyte to the interface more easily, some AC current can pass through the two molecule thick interface without causing electrolysis. However, since a DC bias is provided, it is expected a high Faradaic ratio can be achieved.


SOME SAMPLE CALCULATIONS

Water has a dielectric constant of about 50, which is large. If Cm is the capacitance of the cell M1, then the total capacitance Ct in the AC portion of the circuit is given by:

   Ct = 1/((1/C1) + (1/Cm)) = (C1 Cm)/(C1 + Cm)

For example, if C1 is made equal to Cm then Ct = 0.5 Cm.

The capacitance of a multi-plate electrolysis cell can be determined by looking at the area Ai and separation Si of each electrolyte gap. The capacitance Ci of gap i is then

   Ci = 50 (8.854 F/m) Ai/Si

So, given plate size of 10 cm by 10 cm and plate separation of 0.1 cm we have:

   Ci = 50 (8.854x10^-12 F/m) (0.1 m)^2 / (0.001 m) = 4.427x10^-9 F

He capacitance Cm of n electrolyte gaps in series is:

   Cm = 1/((1/C1) + (1/C2) + ... + (1/Cn))

Given 12 equal sized gaps like the above for Ci we have:

   Cm = 1/(12/Ci)  = Ci/12 = 3.689x10^-10 F

Using C1 = Cm we have:

   Ct = 0.5 Cm = 1.845x10^-10 F

Now to consider a toroidal air core transformer. Assume the conductor is made of tubing about 0.5 cm diameter. Small radius of the torus is 4 cm. Inner radius of torus is 15 cm. Major radius Mr is thus 19 cm. and outer radius is 23 cm. Total turns N = 45. Coil area A is about 50 cm^2. Coil conductor length is about 11.3 m. Inductance is approximated by:

   L = u N^2 A (1/Mr) (1.26x10^-6 H)

   L = (1) (45^2) (50) (1/(19)) (1.26x10^-6 H)

   L = 6.71 mH

Resonant frequency f is

   f = 1 / (2 Pi * (L C)^(1/2))

     = 1 / (2 * 3.14159 * ((6.71x10^-3 H) *  (1.845x10^-10 F))^(1/2))

     = 1.43x10^5 Hz = 143 kHz

This frequency may be a bit high to be practical, and certainly requires good shielding. It appears a ferrite core transformer is most likely the best option. If the inductance is increased by a factor of 100 the frequency drops by a factor of 10, so for a 0.671 H transformer secondary:

   f = 14.3 kHz

An alternative means to drop the frequency is to make the plates larger and use fewer in sequence.

One good thing about using high frequencies is the filters Fi get cheaper and smaller. Choice of frequency may be important. Puharich , US Patent 4,394,230 (1983) used a rectified AM signal, and found resonances in pure water at 3,980 Hz, and octaves 7,960, 15,920, 31840, and 63,690 Hz. It is notable that running all those octave overtones gives a lazy (triangular half cycle) sawtooth wave. It has been conjectured that is why Stanley Meyer operated at around 16,000 Hz. Frequencies between 9 kHz and 150 kHz work well.


Horace Heffner
http://www.mtaonline.net/~hheffner/



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