epsilon = d phi/dt = d (L * v * B)/dt"
That should b: "The i L vector that generates the torque(motive force) moves sideways through the B (or vice versa) at velocity v, creating back emf epsilon, which by Faraday is:
epsilon = d phi/dt = (L * v * B)" Best regards, Horace Heffner http://www.mtaonline.net/~hheffner/
