On Dec 17, 2011, at 10:53 AM, Mark Iverson-ZeroPoint wrote:
How does one explain the observation that the energy involved with
interactions of electrons is a million times less than nuclear
interactions,
and yet the 'electric' charges are 'equal' (and opposite). I would
argue
that there is no 'electric charge'; charge cannot be separated from
the e or
p 'objects'.
I think this is primarily a matter of the *range* of the interactions.
If you look at the deflated states you can see the electron involved
has a mass similar to that of the nucleating particle, be it proton,
deuteron, or quark. The physical parameters of these states are
shown in approximate form here:
http://www.mtaonline.net/~hheffner/FusionSpreadDualRel.pdf
http://mtaonline.net/~hheffner/DeflateP1.pdf
http://www.mtaonline.net/~hheffner/FusionUpQuark.pdf
I had hoped to develop a more accurate and dynamic model, with
compensation for the distribution of charge in the particle
wavefunction, but this has been on a back burner for some years now.
At close range extremely high velocities and relativistic gammas are
involved. For example, the proton mass to electron mass ratio is
given as 1.06983, and its gamma is 2.62791e+4. Further, the presence
of an electron in a Ni nucleus diminishes its electro-magnetic field
mass-energy by MeV levels.
Another consideration may be that a large portion of the binding
energy of a nucleus can be shown to be due to the Casimir force.
This is an electromagnetic effect, and one not fully appraised in
typical models of the nucleus I think.
Best regards,
Horace Heffner
http://www.mtaonline.net/~hheffner/
