On 2012-01-06 03:11, Daniel Rocha wrote:
Well, but, P=V^2/R, so resistance going down, means power going up...
That is not the point. This effect is correlated with *excess* heat (regardless of input power), Celani says.
Cheers, S.A.
On 2012-01-06 03:11, Daniel Rocha wrote:
Well, but, P=V^2/R, so resistance going down, means power going up...
That is not the point. This effect is correlated with *excess* heat (regardless of input power), Celani says.
Cheers, S.A.