Repulsive interactions between neutrons
To set the stage, the standard model of particle physics says that neutrons attract each other. >From an idea from an outlier (our kind of people) in the field of physics Dr. O, Maneul as follows: “Neutrons and protons in the nucleus work like the north and south ends of magnets,” Manuel explains. “Neutrons repel neutrons, protons repel protons, but neutrons attract protons. Neutron repulsion is the force that energizes neutron stars. This empirical fact was discovered by five graduate students working with me to decipher the nuclear mass data for the 2,850 known nuclides in the spring of 2000.” http://www.omatumr.com/abstracts2004/nuclearclustering.pdf Nuclear clustering and interactions between nucleons Other papers by Dr. Maneul as follows: http://www.youtube.com/watch?v=sXNyLYSiPO0 http://arxiv.org/pdf/1102.1499v1 http://www.omatumr.com/abstracts2003/jfe-neutronrep.pdf My theory about how electrostatic screening of the nucleus can produce energy through nuclear fission and neutron breakup. To start out with, we cannot keep loading neutrons into a nucleus without limit because they will eventually be repelled by a mismatch with the resident collection of bound protons. So, more or less, protons and neutrons must be paired inside a nucleus. Any mismatched nucleon is expelled from the nucleus. In Cold Fusion, when all the positive charges of the protons are screened from the nucleus by a large collection of electrons, Could it be that the protons become neutrons by catalyzing a color change though gage boson mediation. The strong force in the nucleus becomes now repulsive and the nucleus and all the nucleons in the nucleus become unstable. This screened nucleus then begins to fall apart because of the short-range repulsive neutron–neutron interactions mediated by the strong force. The neutrons now mostly converted to neutrons in that nucleus begin to disintegrate into hydrogen atoms. >From Dr. Maneul: The disintegration of a neutron can generate up to 3% of its rest mass into energy. This expositon say it far better than I can. The case for neutron repulsion as follows: http://www.applet-magic.com/neutronrepulsion.htm Cheers: Axil On Sat, Jun 16, 2012 at 11:05 PM, David Roberson <dlrober...@aol.com> wrote: > Earlier I made a posting about the addition of a proton or neutron to a > stable isotope and observed that if one of these new compositions is stable > then the other one must not be. This observation holds throughout the > entire list of elements on the chart that I have been referencing. Now I > have a hypothesis as to why this is true. > First of all, it is important to note that the above additions result in a > new element or isotope that has one additional nucleon. After completing > a great deal of research on the subject I see that a group of elements that > share the same number of nucleons have an interesting behavior. They > exhibit energy levels like an electron cloud around a single nucleus. A > minimum energy level (ground level) is always present and adjacent elements > are always at a higher level. It takes one beta plus or minus decay to > get between these adjacent levels and it appears that this will be > energetically favored and always occur at some future time. The time > frame for this decay might be quite extensive, but it will be measurable in > the form of radioactivity. I think of this process as a lot like the > decay of electrons from higher energy levels which eventually get to the > ground state. > I constructed an equation that can be used to find the expected number of > nucleons as a function of the number of protons within a nucleus. I > restricted the range of protons so that it eliminates the very few proton > case and also stops at a proton count of 40 so that I can concentrate the > research to the region to which I am interested and to improve the curve > fit substantially. > I then transformed the above expected nucleon number verses proton count > into the reverse relationship. In this manner I can enter the nucleon > count and calculate the proton and neutron numbers that ideally support it. > As an example, if I enter a nucleon count of 40 I arrive at an expected > proton count of 19 and an associated neutron count of 21. The element > that this chooses is potassium 40. Now this should be the location of > the minimum energy level or ground state for 40 nucleons. The > interesting thing I observed is that this element is unstable with a very > long half life. My explanation is that the number of protons and the > number of neutrons are both odd so they cannot pair up. The resulting > mismatch reduces the binding energy enough that it actually falls below the > adjacent elements of Calcium 40 and Argon 40 which each have an even count > of both types of nucleons. Also, it is apparent that the fall off rate > of binding energy verses error in nucleon ideal distribution is such that > the next element on each side of the two above has less binding energy than > these ideal ones. For this reason I propose that a beta type decay > process will eventually yield one of the two stable levels one step at a > time as each decay takes place. > It should be noted that this odd proton, odd neutron count situation is > virtually always unstable. And likewise the even proton, even neutron > case is similarly always stable when it occurs at the ideal count position. > When just one of these counts is even the elements tend to be stable, but > less so. > I have not reviewed the cases where other types of decays are present and > that might yield fertile ground for future research. > The conclusion I draw from my search is that there will not be a case > where the addition of a proton or a neutron from a currently stable element > will both result in a stable new isotope or element. One or the other of > these processes has less binding energy and a beta plus or beta minus decay > will point to it. There are conditions where neither new product is > stable, but these are fairly rare. > I plan to analyze the decay times of the energy steps in these nuclear > configurations and compare them to the time frames for electron energy > level steps. The levels of energy events within the nucleus are > enormously larger than chemical ones but the decay times are likewise much > longer. These characteristics seem to be contradictory. > Dave > > > >
