I can't resist: What power level is required to get that device to barely enter the visible wavelengths (700nm), again, assuming no losses other than black body?
again using http://www.ajdesigner.com/phpwien/wien_equation_t.php at 700nm: blackbody temperature (T) = 4139.6692857143 kelvin q=2.40137205*10^-9*pi*(Th^4-Tc^4) q=2.40137205*10^-9*pi*(2.9367203218388994*10^14-Tc^4) ; subst(4139.6692857143, Th) q=705199.0585641474*pi q=2.2154481E6W Yeah, Rossi had a really high frequency power supply pumping even 1/10th of that into the E-Cat HT. On Wed, May 22, 2013 at 6:40 PM, James Bowery <[email protected]> wrote: > One final erratum (hopefully): In the November run when the device > overheated to visible wavelengths, the input power was 1kW (p2), not 360W. > Therefore: > > 360=2.40137205*10^-9*pi*(Th^4-6975757441) > 1000=2.40137205*10^-9*pi*(Th^4-6975757441) ; subst(1000, 360) > > Th=(59549289748750/pi+997533314063)^(1/4)/143^(1/4) ; solve(Th) > Th=611.17587 Kelvin > Th=338.026 Celsius > > using: http://www.ajdesigner.com/phpwien/wien_equation.php > > peak emission wavelength (λmax) = 4.741300568689E-6 meter > > Still deep into the infrared. > > > > > On Wed, May 22, 2013 at 5:59 PM, James Bowery <[email protected]> wrote: > >> Erratum: I also left out the substitution step for room temperature: >> >> 360=2.40137205*10^-9*pi*(Th^4-6975757441) ; subst(289) >> >> >> On Wed, May 22, 2013 at 5:53 PM, James Bowery <[email protected]> wrote: >> >>> Erratum: Strike the "So, what..." >>> >>> >>> On Wed, May 22, 2013 at 5:53 PM, James Bowery <[email protected]>wrote: >>> >>>> q=eps*s*(Th^4-Tc^4)*A >>>> q=eps*(2*pi*r^2+2*l*pi*r)*s*(Th^4-Tc^4) ; subst(2*pi*r^2+2*l*pi*r, A) >>>> q=5.6703*10^-8*eps*(2*pi*r^2+2*l*pi*r)*(Th^4-Tc^4) ; subst(5.6703e-8, >>>> s) >>>> q=5.6703*10^-8*eps*(0.11*l*pi+0.00605*pi)*(Th^4-Tc^4) ; subst(.055, r) >>>> q=2.40137205*10^-9*eps*pi*(Th^4-Tc^4) ; subst(.33, l) >>>> q=2.40137205*10^-9*pi*(Th^4-Tc^4) ; subst(1, eps) >>>> 360=2.40137205*10^-9*pi*(Th^4-Tc^4) ; subst(360, q) >>>> Th=(21437744309550/pi+997533314063)^(1/4)/143^(1/4) ; solve(Th) >>>> Th=483.6006 Kelvin >>>> Th=210.451 Celsius >>>> >>>> using: http://www.ajdesigner.com/phpwien/wien_equation.php >>>> >>>> peak emission wavelength (λmax) = 5.9920696955297E-6 meter >>>> >>>> or 6 micrometers >>>> >>>> That is with no losses other than black body radiation (ie: no >>>> convective losses). >>>> >>>> That is way into the infrared. The excursions into the visible >>>> wavelength occurred with 360W. >>>> >>>> >>>> >>>> So, what >>>> >>>> >>>> On Wed, May 22, 2013 at 4:19 PM, Jed Rothwell <[email protected]>wrote: >>>> >>>>> James Bowery <[email protected]> wrote: >>>>> >>>>> >>>>>> There is value in pursuing reductio ad absurda when they engage one >>>>>> of the strongest arguments that the demonstration is valid: >>>>>> >>>>>> That the power input could not conceivably have produced the >>>>>> radiation wavelengths observed. >>>>>> >>>>> >>>>> You have mentioned that several times. Can you please post a more >>>>> detailed discussion of that, with equations and examples? That would be >>>>> helpful. Please post this in a new thread so I can find it easily. >>>>> >>>>> You might also address the fact that the first device melted. >>>>> >>>>> - Jed >>>>> >>>>> >>>> >>> >> >
