It doesn't make sense to call them "magnetic" rather than "electromagnetic" fields if the variation in the magnetic field is rapid. Moreover, a mere magnetic field is not going to disrupt electronics in general -- its EM fields that do that.
On Wed, Jul 24, 2013 at 9:55 AM, Teslaalset <[email protected]>wrote: > The magnetic fields may be very high frequent which will cause eddy > currents in the shielding plates, creating counter magnetic fields, > resulting in strongly reduced magnetic interference. In that sence > shielding will work. > > Op woensdag 24 juli 2013 schreef David Roberson ([email protected]) het > volgende: > > Good point Eric. But keep in mind that a Faraday shield would not stop a >> magnetic field. They can eliminate electrostatic fields, but not magnetic >> ones unless the field is at a very high frequency. This is an important >> piece of the puzzle if true. >> >> Dave >> >> >> -----Original Message----- >> From: Eric Walker <[email protected]> >> To: vortex-l <[email protected]> >> Sent: Wed, Jul 24, 2013 1:45 am >> Subject: Re: [Vo]:Ni 61 does not react. (Ideas why this would be?) >> >> On Tue, Jul 23, 2013 at 10:25 PM, Axil Axil <[email protected]> wrote: >> >>> Today, Defkalion stated that the reactor packs huge magnetic fields >>> capable of disrupting all electronic equipment in the general vicinity of >>> the reactor core. The core had to be shielded by a double ply faraday cage. >>> That huge field is produced by nano-particles in a bath of infrared >>> radiation. >>> >> This makes it sound like there is a current of some kind. If so, that >> is a point in favor of energetic particles (coherent groups, perhaps) and a >> point against slow deuterium/helium formation, which, presumably, would not >> produce currents (unless I'm misunderstanding an implication). >> >> Eric >> >>
