I suspect that a change of the temperature of the incoming water will cause a 
disturbance to the loop.  Rossi must allow sufficient margin for his drive to 
account for this behavior since it will no doubt be encountered.  It would be a 
good idea for him to control the coolant flow rate on the fly as a means to 
compensate for this type of change.  
 

 Rossi now discusses having the internal temperature at around 1000 C while the 
coolant is heated up to 500 C.  I have long waited for him to make such a 
statement since the earlier testing did not indicate this situation.  Of 
course, he allowed radiation to cool the hot cats which now must be designed to 
work at a reasonable cooler output temperature.  The thermal resistance of this 
heat flow path directly impacts the positive feedback loop and must be 
controlled for a reliable product.

As I mentioned previously, he would be wise to keep the coolant at a zero flow 
rate condition at startup to enable the positive feedback to begin at a lower 
net temperature and input power.  The coolant could be heated quickly under 
this condition at the lower input power level.  The thermal masses of the 
system components and the coolant itself would retard the temperature rate of 
rise which would give him time for his control loop to initially stabilize.  It 
is not clear whether or not the coolant should be rapidly allowed to resume 
flow at its design value.  The shape of the flow transition might be used to 
his advantage.

The mention of negative resistance is a subject that I am comfortable with.  I 
have used this type of analysis for many years in the design of oscillator 
networks.  In the ECAT case, it is required in order for the COP to be much 
greater than unity.  Positive resistance appears in the form of heat 
transferring into the coolant.  At a given temperature, the thermal resistance 
can be expressed in a differential form.  The slope of the curve that defines 
core node temperature as a function of heat output power being absorbed by the 
load is one of the important factors in determining the net resistance of the 
system.  This slope at a given temperature yields the positive load thermal 
resistance seen by the core.  The internal power generation process of the core 
itself yields the other resistance term.  That one is negative since heat power 
is being generated by the core in greater quantities as the temperature rises.  
The slope again is also important and represents the instantaneous negative 
resistance at a given core temperature.

The interaction of the input heating power with the balance of the system is a 
bit complex but important.   It determines the temperature at which the 
positive feedback takes control.  It likewise allows control of the complete 
system as discussed in previous posts.

Dave

 

-----Original Message-----
From: MarkI-Zeropoint <zeropo...@charter.net>
To: vortex-l <vortex-l@eskimo.com>
Sent: Thu, Jan 2, 2014 1:44 pm
Subject: RE: [Vo]:Linear Operation of ECAT Modeled


Sounds like one of Rossi's controllability issues may come from the temperature 
stability of the cooling fluid itself.  


Dave's explanation sounds as if the control loop is expecting a rather 
consistent cooling fluid inlet temperature... and that may be the case if 
running off the city water supply (at least no major differences in water temp 
for a running faucet), but if one gets a sudden drop of several degrees on 
inlet water temp, what will that do to the control loop??? 


-Mark Iverson



On Thu, Jan 2, 2014 at 10:33 AM, Jones Beene wrote:


   
From: David Roberson 


Could you offer a simple description of the behavior of the negative 
differential resistance function that you mention?  
  
Looks like you are already doing something similar. Wiki has an entry for the 
electronic version. The image of the curve is an ascending double hump, so if 
your model accommodates that already, then that may be why it is so intuitive. 
If one is plotting P-in vs. P-out then there is good control functionality to 
the top of the first hump, where the negative feedback would start to show 
itself. 
  
https://www.google.com/search?q=negative+differential+resistance&client=firefox-a&hs=bBT&rls=org.mozilla:en-US:official&tbm=isch&tbo=u&source=univ&sa=X&ei=JKTFUo6jBcvxoASVpoCABw&ved=0CDwQsAQ&biw=1146&bih=675
 
  

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