This assumes insulating it will have no adverse effect on the "new fire",
but excessive insulation could extinguish it.
A good test to perform on the Hotcat would be to add the insulation *after*
start up.

Harry

On Fri, Oct 17, 2014 at 10:24 PM, <jwin...@cyllene.uwa.edu.au> wrote:

> I don't know why Rossi doesn't do this.  I think he must hardly have any
> ingenuity - or the scientists/engineers that are in a position to advise
> him!  (Or you could think of more insulting terms).
>
> To convert the output heat to electricity, and then convert it back to
> input heat would have to be the craziest approach imaginable to use!
>
> To feed the output heat back in as input heat all you need to do is
> insulate the device.  What could be easier than that!?
>
> Then to stop it running away and melting down all you need to do is pump
> water or blow gas through it to cool it down in a controlled manner with a
> thermostatically controlled switch (which could even be a passive device
> like the old thermostats used in the cooling systems of auto-mobile
> engines).  The cooling necessary to prevent melt-down represents your
> output energy.
>
> If you need some electrical "excitation" in addition to plain old
> resistive heating, then this would be a very small component and could
> easily be subtracted from the output energy to determine the energy
> balance.  But the fact that the system "runs away" if it is allowed to get
> too hot - even after the "excitation" has been turned off - proves that
> this "excitation" is not really required.
>
> On 18/10/2014 7:32 AM, Paul Breed wrote:
>
>> Closing the loop with a hot side temperature of 1200C and a COP of 3, is
>> right on the very edge of possible...
>>
>> You need close to 50% of theoretical carnot efficiency...
>>
>> 100C cold 1200C hot gives carnot of  0.76
>>
>> Best possible heat to mechanical work..  (3*.76) = 2.28
>> Best possible Work to electricity   0.95
>>
>> gives 2.116   so to break even close the loop and have ZERO excess energy
>> you would need to get to 46% of carnot
>> Commercial large scale power plants don't get to 46% of carnot....
>>
>> Using something really simple like thermo electric (seebeck)  generator
>> would require a COP of  20.2 to get to break even
>> assuming that electrical conversion efficency was 99%
>>
>
>

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