Sorry Jeff, You weren't talking to yourself, I wasn't around this weekend
To continue your example:
$ var=value
$ ref=var
$ echo ${!ref}
value
$ var=newvalue
echo ${!ref}
??????
I don't have bash at work so I can't determine what the output is of the
above. I'm running ksh on an HP, and the ${!ref} doesn't work
Thanks
Jay
----- Original Message -----
From: "Jeff Newmiller" <[EMAIL PROTECTED]>
To: "vox-tech" <[EMAIL PROTECTED]>
Sent: Saturday, January 26, 2002 10:49 PM
Subject: Re: [vox-tech] ksh question
> Sorry to carry on a conversation with myself, but I said...
>
> On Sat, 26 Jan 2002, Jeff Newmiller wrote:
>
> [...]
>
> > In bash, you can do:
> >
> > $ var=value
> > $ ref=var
> > $ echo ${!ref}
> > value
> >
> > but unfortunately, you cannot do
> >
> > $ ${!ref}=anothervalue
>
> and after experimenting further, I find that the effect can be obtained
> with:
>
> $ eval $ref=other
> $ echo $var
> other
>
> This is still more like a pointer in C than a reference in C++.
>
> --------------------------------------------------------------------------
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