On Sun, Jun 28, 2015 at 8:49 PM, Peter Hutterer <peter.hutte...@who-t.net> wrote:
> > + if (elm->next == NULL && elm->prev == NULL) > + return; > + > elm->prev->next = elm->next; > elm->next->prev = elm->prev; > elm->next = NULL; > You probably don't need to check both pointers, as the code will crash if only one of them is NULL.
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