Phyo is trying to build a bot! ;-)
On Thu, Nov 13, 2008 at 1:45 PM, Phyo Arkar <[EMAIL PROTECTED]>wrote:
> Dear Ceej
>
> I would like to upload to a form , from a python script. (Client side)
>
> Web2py do no thave upload (as client) rite?
>
> Thanks for reply anyways.
>
> Regards,
>
> Phyo.
>
>
> On Thu, Nov 13, 2008 at 7:15 PM, ceej <[EMAIL PROTECTED]> wrote:
>
>>
>> Phyo,
>>
>> To get the data from the form that's submitted you can to
>> request.vars.file.file.read():
>>
>> And to write it to uploads you can do something like
>>
>> _folder='%(folder)suploads/'%{'folder': request.folder}
>> main_token=md5.new(str(datetime.datetime.now
>> ())).hexdigest()
>> if not os.path.exists(_folder):
>> os.makedirs('%sfile'%(_folder))
>> file = open('%syou_can_make_a_name.jpg'%(_folder), 'wb')
>> file.write(request.vars.file.file.read())
>> file.close
>>
>> On Nov 13, 10:33 am, "Phyo Arkar" <[EMAIL PROTECTED]> wrote:
>> > Dear All;
>> >
>> > How can i upload multipart form data files in python (web2py?)
>> >
>> > I cannot do it with
>> >
>> > urllib.urlencode
>> > urllib2.urlopen(url,data)
>> >
>> > Files will not be uploaded , just urls will b posted ..(server backend
>> is
>> > php)
>> >
>> > def upload(torrentfile,nfofile,subgenre='Minimal',type=10):
>> > nfo_file=file(nfofile)
>> > torrent_file=file(torrentfile)
>> > data = {'nfo': nfo_file,
>> > 'desc': "",
>> > 'file': torrent_file,
>> > 'type': type,
>> > 'subgenre' : subgenre
>> > }
>> > uldata =urllib.urlencode(data)
>> > req = urllib2.Request(upload_url,uldata)
>> > resp = urllib2.urlopen(req)
>> > result = resp.read()
>> > print result
>>
>>
>
> >
>
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