Hello folks! :)
I am trying to run web2py as Windows service, but no positive results.
Following the recipe on the online book, I edited the file "options.py".
The file looks like that:
#!/usr/bin/python
# -*- coding: utf-8 -*-
import socket
import os
ip = 127.0.0.1
port = 8000
interfaces = [('127.0.0.1', 8000)]
password = '<recycle>'
pid_filename = 'httpserver.pid'
log_filename = 'httpserver.log'
profiler_filename = None
ssl_certificate = None
ssl_private_key = None
#numthreads = 50 # ## deprecated; remove
minthreads = None
maxthreads = None
server_name = socket.gethostname()
request_queue_size = 5
timeout = 30
shutdown_timeout = 5
folder = os.getcwd()
extcron = None
nocron = None
When I install the service, everything seems to be OK:
C:\Users\David\Desktop\myapp\web2py>web2py.exe -W install
web2py Web Framework
Created by Massimo Di Pierro, Copyright 2007-2012
Version 2.2.1 (2012-10-21 16:57:04) stable
Database drivers available: SQLite(sqlite3), MySQL(pymysql), PostgreSQL(
pg8000),
MSSQL(pyodbc), DB2(pyodbc), Teradata(pyodbc), IMAP(imaplib)
Installing service web2py
Changing service configuration
Service updated
But when I launch the service, something goes wrong:
C:\Users\David\Desktop\myapp\web2py>web2py.exe -W start
web2py Web Framework
Created by Massimo Di Pierro, Copyright 2007-2012
Version 2.2.1 (2012-10-21 16:57:04) stable
Database drivers available: SQLite(sqlite3), MySQL(pymysql), PostgreSQL(
pg8000),
MSSQL(pyodbc), DB2(pyodbc), Teradata(pyodbc), IMAP(imaplib)
Starting service web2py
Error starting service: The service did not respond to the start or control
requ
est in a timely fashion.
Can anybody help me in that? :)
Cheers,
David
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