Sorry I do not have a good solution at the moment. Can you open a ticket about this so we'll will not forget. For now you may want to consider creating a database view and selecting from the view. You would need to create a model (readonly) to access the view.
On Wednesday, 19 December 2012 16:19:33 UTC-6, Mamisoa Andriantafika wrote: > > Best results to UNION I could have was using the mutex table trick: > http://www.xaprb.com/blog/2006/05/26/how-to-write-full-outer-join-in-mysql/ > with this syntax: > > exams_mutex = db().select(db.dataset1.ALL, db.dataset2.ALL, > left=[db.dataset1.on(db.mutex.i==0),db.dataset2.on(db.mutex.i==1)]) > > Two problems left: > > 1- how to merge the 2 date columns > 2- how to order then by date > > SQL answer is there: > > http://stackoverflow.com/questions/8245630/mysql-combine-two-date-fields-and-then-order-by > > SELECT > [some info], > GREATEST( ticket_date, ticket_history_date ) as latest_date > FROM > [tables and join] > ORDER BY > latest_date > > > Is is possible using to process it using DAL? > > Le dimanche 16 décembre 2012 17:40:22 UTC+1, Mamisoa Andriantafika a > écrit : >> >> Sorry I still get: "Cannot | incompatible Rows objects". >> >> I'll change the field name "date" you are very right. >> >> Le dimanche 16 décembre 2012 15:49:57 UTC+1, Massimo Di Pierro a écrit : >>> >>> My bad. Thry this: >>> >>> fields1 = [db.dataset1.date, db.dataset1.param1, db.dateset1.patient_id] >>> fields2 = [db.dataset2.date, db.dataset2.test1, db.dateset2.patient_id] >>> rows = ( db(db.dataset1).select(*fields1) | >>> db(db.dataset2).select(*fields2) ).sort(lambda row: row.date) >>> >>> Mind that having a column called "date" will result in major headaches >>> in the future. >>> >>> On Sunday, 16 December 2012 03:15:46 UTC-6, Mamisoa Andriantafika wrote: >>>> >>>> Hi again, >>>> >>>> "|" seems not to work because the column numbers is different between >>>> the 2 tables? >>>> >>>> >>>> Le samedi 15 décembre 2012 20:23:44 UTC+1, Massimo Di Pierro a écrit : >>>>> >>>>> If you have lots of records you may be able to do it with a database >>>>> view but that may be db specific. >>>>> >>>>> If you don't have too many records you can do: >>>>> >>>>> rows = ( db(db.dataset1).select() | db(db.dataset2).select() >>>>> ).sort(lambda row: row.date) >>>>> >>>>> >>>>> >>>>> On Saturday, 15 December 2012 08:43:35 UTC-6, Mamisoa Andriantafika >>>>> wrote: >>>>>> >>>>>> Hi, >>>>>> >>>>>> I have this db model: >>>>>> >>>>>> db.define_table('patients', >>>>>> Field('name', 'string', length=32), >>>>>> Field('firstname', 'string', length=32), >>>>>> Field('dob', 'date'), >>>>>> format='%(name)s') >>>>>> >>>>>> db.define_table('dataset1', >>>>>> Field('date', 'date', length=32), >>>>>> Field('param1', 'string', length=50), >>>>>> Field('param2', 'string', length=50), >>>>>> Field('patient_id', db.patients, writable=False, readable=False)) >>>>>> >>>>>> db.define_table('dataset2', >>>>>> Field('date', 'date', notnull=True), >>>>>> Field('test1', 'text'), >>>>>> Field('patient_id', db.patients, writable=False, readable=True)) >>>>>> >>>>>> I'd like to show in one view, for 1 patient_id, all the corresponding >>>>>> dataset1 and dataset2 ordered by date. >>>>>> >>>>>> What query should I use? Do I have to use an intermediate table >>>>>> 'history' to record each activity in dataset1/2 to get a result? >>>>>> >>>>>> Thanks for help. >>>>>> >>>>> --
