SQLFORM.grid "takes" the labels from the underlying model, so as long as
you specify the label before calling the grid, you're fine.
db.table1.field1.label = 'whatever'
grid = SQLFORM.grid(db.table1)
should work.
On Tuesday, March 26, 2013 12:07:29 PM UTC+1, Andrii Pitukh wrote:
>
> Can you write a code example? SQLFORM constructor has 'labels' parameter,
> but SQLFORM.grid doesn't have it.
>
> On Tuesday, March 26, 2013 12:20:10 PM UTC+2, Niphlod wrote:
>>
>> the form has normally the label of that field ..... headers are for the
>> table representation only
>>
>> On Tuesday, March 26, 2013 11:01:03 AM UTC+1, Andrii Pitukh wrote:
>>>
>>> I created the following form:
>>>
>>> SQLFORM.grid(dbm.groups_subjects, headers={'table1.field1':T('Myname1'))
>>>
>>> The names of columns that are set in headers are shown correctly (I see
>>> *Myname1* as header). But when I press view or create, I see '*field1*'
>>> as column header instead of *'Myname1'*
>>>
>>
--
---
You received this message because you are subscribed to the Google Groups
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to web2py+unsubscr...@googlegroups.com.
For more options, visit https://groups.google.com/groups/opt_out.
