So, if I do understand correctly the Niphold explanation if I want to
search for instance the first_name of the auth_user table that is
referenced from my table I can't just pass the to SQLFORM.grid my_table, I
better pass it a join query where all the represent are replaced with the
really field of the referenced table, right?

Richard


On Mon, Aug 6, 2012 at 4:25 PM, Niphlod <niph...@gmail.com> wrote:

> reeeeeally don't know if this is officially supported or not, but works in
> a test I just made.
>
>
> On Monday, August 6, 2012 10:06:44 PM UTC+2, Cliff Kachinske wrote:
>>
>> Maybe I missed something here.
>>
>> I know you can pass a query to grid.  By queryset do you mean a set of
>> row objects?
>>
>> On Monday, August 6, 2012 3:56:12 PM UTC-4, Niphlod wrote:
>>>
>>> this is more related to an implementation logic than a bug.
>>>
>>> fields that are represented by some other field gets computed at
>>> run-time, but to search/orderby them you have to fetch them too, and that
>>> can be expensive.
>>>
>>> If you need to orderby/search by a referenced/represented/**computed
>>> field, you can pass the full queryset to the grid.
>>>
>>> On Monday, August 6, 2012 9:07:59 PM UTC+2, Cliff Kachinske wrote:
>>>>
>>>> Me too.  It's one of the reasons I don't use grid/smartgrid.
>>>>
>>>> Sorry I don't have an answer.
>>>>
>>>> On Monday, August 6, 2012 10:18:07 AM UTC-4, weheh wrote:
>>>>>
>>>>> I have an SQLFORM.grid(... orderby=db.host.id ...) where
>>>>> db.host.id.represent=lambda value, row: int(
>>>>>     db((db.url_queue.host_id == value) & (db.url_queue.removed ==
>>>>> None)).count()
>>>>>     )
>>>>>
>>>>> The host.id column displays the correct numbers, but when I click on
>>>>> the column title to order ascending or descending, the order is seemingly
>>>>> random. I suspect it's ordering not by the lambda value, but rather by the
>>>>> underlying host.id value. Seems like a bug ...?
>>>>>
>>>>  --
>
>
>
>

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