there are multiple errors (and lots of unnecessary parenthesis).
first of all, define a single function to represent your value....
def represent_colored(value):
if value == 1:
return ...... <--green
elif value == 2:
....yellow
elif value == 3:
....red
else:
.....purple (just to spot occasional errors)
Then, apply the represent
db.table.field.represent = lambda row, value : represent_colored(value)
Then, show the grid, and it should work.
The grid doesn't "take" as rows your executesql statement (that returns a
resultset, not a query as intended), so those definitions you made don't
work as you expected.
On Monday, June 10, 2013 7:31:04 PM UTC+2, keep...@gmail.com wrote:
>
> Thanks for the reply, Niphlod.
>
> Now there was the following question:
>
> I add the following lines to the controller before the grid = SQLFORM.grid
> ...
>
> warn = db.executesql ('SELECT t.level_warn FROM TEMPER_RC t;')
> for val in warn:
> if (val == (1)):
> db.TEMPER_RC.level_warn.represent = lambda value, row: (B (DIV
> (str ('1 '% row if row else''), _style =' background: # 339933 ')))
> elif (val == (2)):
> db.TEMPER_RC.level_warn.represent = lambda value, row: (B (DIV
> (str ('2 '% row if row else''), _style =' background: # FFFF33 ')))
> else:
> db.TEMPER_RC.level_warn.represent = lambda value, row: (B (DIV
> (str ('3 '% row if row else''), _style =' background: # FF0000 ')))
>
> But only fulfills the first condition, and all the fields level_warn
> colored in green. Moreover, the condition fulfills wrong, because the first
> row in the table has a value of 3, that is, the field must be painted red!
>
> What am I doing wrong?
>
>
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