It may be an issue with buffer size. Try import shutil shutil.copyfileobj(request.vars.filename,open(path,'w'))
Massimo On May 8, 2:56 pm, Hans <johann.scheibelho...@easytouch-edv.com> wrote: > There is a problem with the following code line > > > open(path,'w').write(request.vars.filename.file.read()) > > It creates the file 'a_dummy_file_name.xls' but it is not the same > size as the original file, for example: > 6790KB original.xls > 6862KB a_dummy_file_name.xls > > If I try to open the dummy file with excel or open office it says the > file is corrupt. > I've tried to copy the file manually right after this code line and > continued execution from there onward...rest works nicely. > > I tried on windows and on ubuntu, seems the same problem. > > Any idea how to solve that issue with the corrupt file (=getting a > exact copy) ? > > thanks, > hans > > On May 7, 10:56 pm, mdipierro <mdipie...@cs.depaul.edu> wrote: > > > This should do > > > def excel_read(): > > result={} > > if request.vars.filename != None: > > try: > > import xlrd > > path=os.path.join > > (request.folder,'private','a_dummy_file_name.xls') > > open(path,'w').write(request.vars.filename.file.read()) > > book = xlrd.open_workbook(path) > > result['The number of worksheets is']=book.nsheets > > result["Worksheet name(s)"]= book.sheet_names() > > sh = book.sheet_by_index(0) > > result['sh.name']=sh.name > > result['sh.nrows']=sh.nrows > > result['sh.ncols']=sh.ncols > > result['Cell D30 is']=sh.cell_value(rowx=29, colx=3) > > for rx in range(sh.nrows): > > result['row ' + str(rx)]=sh.row(rx) > > except: > > response.flash = T('excel_read exception') > > return dict(result=result) > > > for you request.vars.filename is a cgi.FieldStorage object. It is not > > a named file. > > It containes > > - request.vars.filename.file (a buffered input stream) > > - request.vars.filename.filename (the original filename) > > For you to access it you should read the stream and save it with a > > name. Do not use the original filename to avoid directory traversal > > attacks. > > > Massimo > > > On May 7, 2:58 pm, Hans <johann.scheibelho...@easytouch-edv.com> > > wrote: > > > > I'm trying to import some content directly from an excel file which > > > the user selects from its local files. I've taken and modified code > > > from the admin controller for retrieving the path/filename thru a nice > > > file selection window. > > > > The problem: I get only the filename of a locked temporary file, not > > > the original filename. If I close the temporary file, to remove the > > > lock, the file is automatically deleted... > > > > I would not mind to work with a temporary copy of the original file, > > > but retrieving the original path/filename thru a similar file > > > selection window would be prefered. How can this be achieved? > > > > Hans > > > P.S. I'm using the xlrd module fromhttp://pypi.python.org/pypi/xlrd > > > > ### viewer ### > > > {{extend 'layout.html'}} > > > <h1>excel_read.html template</h1> > > > > <div class='frame'> > > > <h2>{{=t2.T('Select File')}}</h2> > > > {{=FORM('File: ',INPUT(_type='file',_name='filename'),INPUT > > > (_type='submit', _value='submit'))}} > > > </div> > > > > <div class='frame'> > > > {{=BEAUTIFY(response._vars)}} > > > </div> > > > > ### controller ### > > > def excel_read(): > > > result={} > > > if request.vars.filename != None: > > > try: > > > import xlrd > > > > # >>> can't locate the originally selected path/filename in > > > request.vars.filename <<< > > > book = xlrd.open_workbook(request.vars.filename.file.name) > > > # >>> with a valid path/filename it works <<< > > > book = xlrd.open_workbook('F:/Documents and Settings/Hans/ > > > Desktop/test.xls') > > > > result['The number of worksheets is']=book.nsheets > > > result["Worksheet name(s)"]= book.sheet_names() > > > sh = book.sheet_by_index(0) > > > result['sh.name']=sh.name > > > result['sh.nrows']=sh.nrows > > > result['sh.ncols']=sh.ncols > > > result['Cell D30 is']=sh.cell_value(rowx=29, colx=3) > > > for rx in range(sh.nrows): > > > result['row ' + str(rx)]=sh.row(rx) > > > except: > > > response.flash = T('excel_read exception') > > > return dict(result=result) --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "web2py Web Framework" group. To post to this group, send email to web2py@googlegroups.com To unsubscribe from this group, send email to web2py+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/web2py?hl=en -~----------~----~----~----~------~----~------~--~---