Hi Anthony
I am not able to get your question. I have one form controller with one
view. http://127.0.0.1:8000/tracker/default/form when i run this url its
show 404 error.
Actually what is my requirement, I have one csv file. which i have to
upload. Before saving the file in database, i want to edit in browser.
After editing i want to save in database. Is there any method to do.
Thanks
On Wednesday, 26 June 2013 19:09:00 UTC+5:30, Anthony wrote:
>
> Using the browser developer tools, what URL gets requested when the ajax
> call is made?
>
> On Wednesday, June 26, 2013 2:44:18 AM UTC-4, Rohitraj Sharma wrote:
>>
>> I want to select some particular table from database in a drop dowan.
>> Then import csv file. edit that file and update. . Can Any one can help me
>> plz
>>
>> i am using the fallowing code for that
>>
>>
>> View
>>
>> <script>
>> jQuery(function() {
>> jQuery('#table').change(function() {
>> web2py_component("{{=URL('default', 'form.load')}}" + "/" +
>> jQuery(this).val(), target='form')
>> })})</script>
>> {{=SELECT('Select a table', *db.tables, _id='table')}}<div id="form"></div>
>>
>>
>> Controller
>>
>> def form():
>> if request.args(0) in db.tables:
>> response.generic_patterns = ['load']
>> return dict(form=SQLFORM(db[request.args(0)]).process())
>> else:
>> raise HTTP(404)
>>
>>
>> every time it toll else part.
>>
>>
>> can any one help me.
>>
>>
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