Oops, sorry, I read that wrong -- thought it was a "represent" function 
rather than a "compute" function. Yes, not sure you want to store a value 
other than the db.series.id value in a reference field for db.series.

Anthony

On Thursday, July 11, 2013 2:39:39 PM UTC-4, Richard wrote:
>
> But in this case you don't have the id of the referenced record as 
> relation key... I am not sure it's what you want. But you question is 
> really vague so difficult to answer correctly to your I think :P
>
> Richard
>
>
> On Thu, Jul 11, 2013 at 2:21 PM, Anthony <abas...@gmail.com 
> <javascript:>>wrote:
>
>> On Thursday, July 11, 2013 1:21:11 PM UTC-4, greenpoise wrote:
>>
>>> I think I saw some light in here!  this did the trick for me:
>>>
>>> Field('supplier', 'reference supplier',compute=lambda row: db.series(row
>>> .series).supplier**),
>>>
>>
>> Should be the same as:
>>
>> lambda row: row.series.supplier
>>
>> assuming row.series is a reference field referring to db.series.
>>
>> Anthony
>>
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