Hi Adi and Javier,
I can't get the syntax to work. Can you please baby me though the phrasing
and just copy the first button twice in this working example so that two
identical buttons appear?
def view_suggestions():
db.Idea.id.represent = lambda id, r: A('Post shared services idea',
_href=URL('add_sharability_info_to_a_suggestion',
vars=dict(filter=id)),_class="btn btn-mini")
is_owner = (lambda row: row.created_by == auth.user_id) if auth.user
else False
grid = SQLFORM.grid(db.Idea,editable=is_owner, deletable=is_owner,
user_signature=True,fields=[db.Idea.ideaShortSummary,db.Idea.created_by,db.Idea.id],
headers={ 'Idea.ideaShortSummary':'Description'}, maxtextlengths={
'Idea.ideaShortSummary':140},links = [dict(header='Post comment',
body=lambda row: A('Post comment',_class="btn btn-mini",
_href=URL('comment_on_a_suggestion', vars=dict(filter=row.id))))]),
return dict(grid = grid)
thanks,
Alex
On Monday, September 16, 2013 7:10:09 AM UTC-7, Adi wrote:
>
> actually, you can also define a table that links apply to. this way you
> won't get the error, when applying functionality to a wrong table...
>
> links=dict(purchase_order=[
> lambda row:(_get_order_details(row)),
> lambda row: A('Duplicate',
> _class='button', _href=URL('duplicate_po',
> args=[row.id])),
> lambda row: A('Print', _class='button', _href=
> URL('print_all',args=[row.id]))
> ],
> other_table=[
> lambda row:(_get_something_else(row)),
> ],),
>
>
>
>
>
>
>
> On Monday, September 16, 2013 9:42:22 AM UTC-4, Javier Pepe wrote:
>>
>> You need pass a list of dict
>>
>> links = [{'header':'', 'body': lambda row:
>> A('',_title='Procesar',_class='icon-refresh',_href=URL(c='planilla',
>> {'header':'', 'body': lambda row:
>> A('',_title='Mail',_class='icon-envelope',_href='index/pedircontadores/%
>> {'header':'', 'body': lambda row:
>> A('',_title='Estado',_class='icon-ok',callback=URL(c='planilla',f='estad
>> {'header':'', 'body': lambda row:
>> A('',_title='Control',_class='icon-check',_href=URL(c='planilla',f='pdf/
>> {'header':'', 'body': lambda row: A('',_title='Control
>> 2',_class='icon-check',_href=URL(c='planilla',f='co
>> {'header':'', 'body': lambda row:
>> A('',_title='PDF',_class='icon-print',_href=URL(f='pdf/%s/%s' % (row.id,
>> {'header':'', 'body': lambda row: A('',_title='PDF
>> distribuidor',_class='icon-print',_href=URL(f='pdf/%s/%
>> {'header':'', 'body': lambda row:
>> A('',_title='Detalle',_class='icon-list',_href=URL(c='detalle',f='index'
>> ]
>>
>>
>>
>> On Sun, Sep 15, 2013 at 9:31 PM, Alex Glaros <alexg...@gmail.com> wrote:
>>
>>> What is syntax for TWO or more buttons? I've tried several variations.
>>> Would it be two "dict" phrases, or two header phrases separated by commas?
>>>
>>> One button will call one function, and the other would call a different
>>> function.
>>>
>>> thanks,
>>>
>>> Alex
>>>
>>>
>>> On Saturday, September 14, 2013 6:56:24 PM UTC-7, Alex Glaros wrote:
>>>>
>>>> Works perfect Adi and Villas,
>>>>
>>>> much appreciated.
>>>>
>>>> Here's the complete code:
>>>>
>>>> def view_all_suggestions_and_**comments():
>>>> query = (db.IdeaComment.ideaID==db.**Idea.id <http://db.Idea.id>)
>>>> & (db.IdeaComment.partyID==db.**Party.id <http://db.Party.id>)
>>>> grid = SQLFORM.grid(query, ,links = [dict(header='Virtual Field',
>>>> body=lambda row: A('Add a comment!',_class="btn btn-mini",
>>>> _href=URL('comment_on_a_**suggestion', vars=dict(filter=row.Idea.id))**
>>>> ))])
>>>> return dict(grid = grid)
>>>>
>>>> Alex
>>>>
>>>>
>>>> On Saturday, September 14, 2013 6:01:33 PM UTC-7, Adi wrote:
>>>>>
>>>>> lambda row: A('Complete',
>>>>> _class='btn', _id='btn_complete',
>>>>> _onclick='return
>>>>> confirm("Complete Order %s? (%s %s)")' % (row.id,
>>>>>
>>>>> row.shipFirstName,
>>>>>
>>>>> row.shipLastName),
>>>>> _href=URL(r=request,f='**
>>>>> complete_order',args=[row.id])**,
>>>>>
>>>>>
>>>>>
>>>>>
>>>>> On Saturday, September 14, 2013 7:41:24 PM UTC-4, Alex Glaros wrote:
>>>>>>
>>>>>> it works correctly Villas, thanks.
>>>>>>
>>>>>> how could I turn "Add a comment!" text into a button. Possible
>>>>>> syntax ",_class="btn btn-mini"", but where does it go?
>>>>>>
>>>>>> thanks,
>>>>>>
>>>>>> Alex
>>>>>>
>>>>>> On Saturday, September 14, 2013 10:23:00 AM UTC-7, villas wrote:
>>>>>>>
>>>>>>> Maybe this would work using row.idea.id like this...
>>>>>>>
>>>>>>> grid = SQLFORM.grid(query,
>>>>>>> links = [dict(header='Virtual Field',
>>>>>>> body=lambda row: A('Add a comment!', _href=URL('comment_on_a_**
>>>>>>> suggestion', vars=dict(filter=row.idea.id <http://row.id/>))**)
>>>>>>> )]
>>>>>>> )
>>>>>>>
>>>>>>>
>>>>>>> You can also now include "virtual fields" in grids, but I haven't
>>>>>>> needed to try that yet.
>>>>>>>
>>>>>>>
>>>>>>>
>>>>>>> On Saturday, 14 September 2013 15:23:49 UTC+1, Alex Glaros wrote:
>>>>>>>>
>>>>>>>> thanks Villas but I receive this error: Row' object has no
>>>>>>>> attribute 'id'
>>>>>>>>
>>>>>>>> perhaps it doesn't know which of the joined "id"s to reference
>>>>>>>>
>>>>>>>> this work-around works because it let's system know which id it is:
>>>>>>>> db.Idea.id.represent = lambda id, r: A('Add a comment!',
>>>>>>>> _href=URL('comment_on_a_sugges**tion', vars=dict(filter=id)))
>>>>>>>>
>>>>>>>> Alex
>>>>>>>>
>>>>>>>> On Saturday, September 14, 2013 4:56:33 AM UTC-7, villas wrote:
>>>>>>>>>
>>>>>>>>> Try this...
>>>>>>>>>
>>>>>>>>> grid = SQLFORM.grid(query,
>>>>>>>>> ** links = [dict(header='Virtual
>>>>>>>>> Field',
>>>>>>>>> ** body=lambda
>>>>>>>>> row: A('Add a comment!', _href=URL('comment_on_a_**suggestion',
>>>>>>>>> vars=dict(filter=row.id)))
>>>>>>>>> ** )]
>>>>>>>>> ** )
>>>>>>>>>
>>>>>>>>>
>>>>>>>>> On Friday, 13 September 2013 21:57:28 UTC+1, Alex Glaros wrote:
>>>>>>>>>>
>>>>>>>>>> I tried this but got "lambda requires 2 args, 1 given" error,
>>>>>>>>>> plus need to be able to pass Idea.id parm to the button. How to do
>>>>>>>>>> that?
>>>>>>>>>>
>>>>>>>>>> grid = SQLFORM.grid(query,links = [dict(header='Virtual
>>>>>>>>>> Field',body=lambda id, r: A('Add a comment!',
>>>>>>>>>> _href=URL('comment_on_a_
>>>>>>>>>> **suggestion', vars=dict(filter=id))))])
>>>>>>>>>>
>>>>>>>>>> On Friday, September 13, 2013 1:33:35 PM UTC-7, villas wrote:
>>>>>>>>>>>
>>>>>>>>>>> Hope this helps...
>>>>>>>>>>>
>>>>>>>>>>> From the book:
>>>>>>>>>>>
>>>>>>>>>>> links is used to display new columns which can be links to
>>>>>>>>>>> other pages. The links argument must be a list of
>>>>>>>>>>> dict(header='name',body=lambda
>>>>>>>>>>> row: A(...)) where header is the header of the new column and
>>>>>>>>>>> body is a function that takes a row and returns a value. In the
>>>>>>>>>>> example, the value is a A(...) helper.
>>>>>>>>>>>
>>>>>>>>>>> Example:
>>>>>>>>>>>
>>>>>>>>>>> linkbtns = [
>>>>>>>>>>> lambda row: SPAN('Mag',_class="label
>>>>>>>>>>> label-success") \
>>>>>>>>>>> if row.status =='Y' else '',
>>>>>>>>>>> lambda row: SPAN('Web',_class="label
>>>>>>>>>>> label-success") \
>>>>>>>>>>> if row.is_active else '',
>>>>>>>>>>> lambda row: A( I('',_class="icon-eye-open")+'
>>>>>>>>>>> View',
>>>>>>>>>>> _href=URL("view",args=[row.
>>>>>>>>>>> id]**),
>>>>>>>>>>> _class="btn btn-small"
>>>>>>>>>>> ),
>>>>>>>>>>> lambda row: A( I('',_class="icon-edit")+' Edit'
>>>>>>>>>>> ,
>>>>>>>>>>> _href=URL("edit",args=[row.
>>>>>>>>>>> id]**),
>>>>>>>>>>> _class="btn btn-small"
>>>>>>>>>>> ),
>>>>>>>>>>> lambda row: A( I('',_class="icon-road")+' Map',
>>>>>>>>>>> _href=URL('default',
>>>>>>>>>>> 'geocoder'**,args=['caclient',row.id],vars**={'title':row.
>>>>>>>>>>> business}),
>>>>>>>>>>> _class="btn btn-small"
>>>>>>>>>>> ),
>>>>>>>>>>> ]
>>>>>>>>>>> grid = SQLFORM.grid(....... links=linkbtns, .......)
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>>
>>>>>>>>>>> On Friday, 13 September 2013 21:00:56 UTC+1, Alex Glaros wrote:
>>>>>>>>>>>>
>>>>>>>>>>>> How do I add a button "Add a comment!" in every row of a grid?
>>>>>>>>>>>> It's a kind of virtual column.
>>>>>>>>>>>>
>>>>>>>>>>>> The below works, it takes user exactly to the correct row in
>>>>>>>>>>>> the next table, but I use up one of the fields (Idea.id). How do
>>>>>>>>>>>> I just
>>>>>>>>>>>> create text/virtual column that doesn't sacrifice existing field?
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> def view_all_suggestions_and_**comments():
>>>>>>>>>>>> db.Idea.id.represent = lambda id, r: A('Add a comment!',
>>>>>>>>>>>> _href=URL('comment_on_a_**suggestion', vars=dict(filter=id)))
>>>>>>>>>>>>
>>>>>>>>>>>> query =
>>>>>>>>>>>> (db.IdeaComment.ideaID==db.**Idea.id<http://db.Idea.id>)
>>>>>>>>>>>> & (db.IdeaComment.partyID==db.**Party.id <http://db.Party.id>)
>>>>>>>>>>>> grid = SQLFORM.grid(query)
>>>>>>>>>>>> return dict(grid = grid)
>>>>>>>>>>>>
>>>>>>>>>>>>
>>>>>>>>>>>> I read the book but need exact syntax for this situation.
>>>>>>>>>>>>
>>>>>>>>>>>> Thanks,
>>>>>>>>>>>>
>>>>>>>>>>>> Alex Glaros
>>>>>>>>>>>>
>>>>>>>>>>> --
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>>
>>
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