try replace
Field.Virtual('anexos', lambda row: "<a href=''>Teste_%s</a>" % row.parte.id
)
with
Field.Virtual('anexos', lambda row: XML("<a href=''>Teste_%s</a>" % row.
parte.id))
or
Field.Virtual('anexos', lambda row: A('Teste_%s'" % row.parte.id,_href=''))
but you may also want to consider using this instead:
db.parte.id.label = "anexos"
db.parte.id.represent = lambda id,row: lambda row: A('Teste_%s'" % id
,_href=''))
On Friday, 27 December 2013 12:23:08 UTC-6, Diego Tostes wrote:
>
> Hi,
>
> I am trying to create a virtualfield as a link like the this code:
>
> http://pastebin.com/c2wZqECH
>
> But when i create a SQL.grid this virtualfield is displayed as a string.
>
> Is it possible to create a link ?
>
> Rgds,
>
> Diego
>
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