Unfortunately, you can't use SQLALL objects in a list like that. Probably
the best you can do is:
rows = db(some_query).select(count, db.table1.ALL, db.table2.ALL, left=left,
groupby='%s, %s' % (db.table1.ALL, db.table2.
ALL))
Anthony
On Tuesday, March 4, 2014 6:08:42 AM UTC-5, Marin Pranjić wrote:
>
> I guess I never did it before, which is weird because it looks like usual
> requirement.
>
> I have a DB query where I need to get a join of two tables and aggregate
> from third table.
> That means I need to set two tables in groupby.
>
> To describe what *doesn't *work but you'll get the idea what I want:
>
> count = db.table3.id.count()
> left = db.table3.on(something)
> rows = db(some_query).select(count, db.table1.ALL, db.table2.ALL, left=
> left, *groupby=[db.table1.ALL, db.table2.ALL]*)
>
> So the groupby thing is not working and I don't see an easy way to do it.
> I could extract fields from SQLALL object but that's not a way to go. It
> should be easier :)
>
> Marin
>
>
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