Hello, I am searching a way to make URL() return an address with HTTP"S" instead of plain HTTP. I didn't find a way to do that...
There is : request.is_https request.requires_https() But they seem to be for preventing access to plain HTTP. So, that mean that URL() always redirect to HTTP and never to HTTPS... That may reduce performance, I had read long time ago that reducing redirection is "rule number 1" for improving loading speed... Maybe it could be a good idea to add a flag that let generate URL() with HTTPS instead of only HTTP?? Richard -- Resources: - http://web2py.com - http://web2py.com/book (Documentation) - http://github.com/web2py/web2py (Source code) - https://code.google.com/p/web2py/issues/list (Report Issues) --- You received this message because you are subscribed to the Google Groups "web2py-users" group. To unsubscribe from this group and stop receiving emails from it, send an email to web2py+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
