Anthony, many thanks!
Can this be achieved also with setting SQLFORM( _action="") attribute?
Best,
Kristjan
On Tuesday, 10 June 2014 15:42:17 UTC+2, Anthony wrote:
>
> The "action" attribute of the form is "#", which means the form will
> submit to the URL of the parent page. Instead, your form must submit to the
> edit_posts action, which means you need to trap the form submission and
> submit it via Ajax as well. The easiest way to do this is to instead put
> the form in a web2py component:
>
> <button class="btn btn-lg" onclick="$.web2py.component('{{=URL('default'
> , 'edit_posts', args=post.id)}}', 'post_form');"> Edit </button>
>
> <div id='post_form'></div>
>
> Anthony
>
> On Tuesday, June 10, 2014 2:06:32 AM UTC-4, Najtsirk wrote:
>>
>> Hi,
>>
>> in my default.py i have a simple function:
>>
>> def edit_posts():
>> form=SQLFORM(db.postos, request.args(0)).process()
>> return dict(form=form)
>>
>> On my posts page, i have a table of all posts with a button, that calls a
>> SQLFORM with a jQuery load, like this:
>>
>> <button class="btn btn-lg"
>> onclick="$('.content').load('{{=URL('default' , 'edit_posts', args=
>> post.id)}}');"> Edit </button>
>>
>> Until here, everything works ok. But the problem is, i canot update a
>> post over this form.
>>
>> SQLFORM, whic is shown ad default/edit_posts/post.id works without
>> problem.
>>
>> What am I missing here?
>>
>> Best,
>> Kristjan
>>
>
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