I'd like to display a link to an existing page when criteria are met. Code
I've written only lists the name of the page - it uses a list - then
returns the contents of the list.
What I have:
def assay_display(row):
assay_list = list()
if db(row.MML.lot == db.amino_acid.lot).select():
assay_list.append('Amino Acid')
What I am trying to do (psuedo code)
def assay_display(row):
assay_list = list()
if db(row.MML.lot == db.amino_acid.lot).select():
assay_list.append.URL('path to url')
Any recommendations on how to approach?
Thank you in advance,
Neub
--
Resources:
- http://web2py.com
- http://web2py.com/book (Documentation)
- http://github.com/web2py/web2py (Source code)
- https://code.google.com/p/web2py/issues/list (Report Issues)
---
You received this message because you are subscribed to the Google Groups
"web2py-users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to web2py+unsubscr...@googlegroups.com.
For more options, visit https://groups.google.com/d/optout.
